In the given figure find the value of all the angles of the kite i. e. angle BAD, angle ADC, angle BCD and angle ABC
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Step-by-step explanation:
In BCD:-
BC = CD.
BCO = DCO = 30 degrees.
BCD = BCO + DCO.
= 30 + 30.
= 30 * 2.
= 60 degrees.
In BAD:-
AB = AD.
ABO = ADO = 50 degrees.
BOA = AOD = 90 degrees. { Diagonals. }
BAO = Sum of angles in the triangle - ( ABO + AOB ).
= Sum of angles - ( 50 + 90 ).
= Sum of angles - 140 degrees.
Sum of angles in a polygon = ( sides - 2 ) * 180 °.
= ( 3 - 2 ) * 180 °.
= 1 * 180 °.
= 180 ° .
BAO = 180 - 140.
= 40 °.
Similarly, OAD = 40 °.
BAD = OAD + BAO
= 40 + 40 ° .
= 80 °.
Sorry, but I cannot solve further.
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