Question

in the given figure find the value of angle theta if ab = 20 CM BC = 20√3cm​

Answer 1

$\textbf{Formula used:}$

$\bf\,tan\theta=\displaystyle\frac{\textbf{Opposite side}}{\textbf{Adjacent side}}$

$\textbf{Given:}$

$AB=20\;\text{cm}$

$BC=20\sqrt{3}\;\text{cm}$

$\text{In \triangle ABC,}$

$\bf\,tan\theta=\displaystyle\frac{\textbf{Opposite side}}{\textbf{Adjacent side}}$

$\implies\,tan\theta=\displaystyle\frac{20}{20\sqrt{3}}$

$\implies\,tan\theta=\displaystyle\frac{1}{\sqrt{3}}$

$\implies\,\theta=30^{\circ}$

$\therefore\textbf{The value of the angle \theta is 30^{\circ} }$

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