Question

In the given figure, find the value of angleA + angleB + angleC + angleD + angleD + angleF.​

Answer 1

Step-by-step explanation:

Given : ∆ACE & ∆BDF

Find value of < A+<B+<C+<D+<E+<F

In ∆ACE

<A+<C+<E= 180°( sum of all < 's property) EQ :1

&

In ∆BDF

<B+<D+<F= ( sum of all < 's property) EQ: 2

From EQ 1&2 we get

<A+<B+<C+<D+<E+<F = 180°+180°

<A+<B+<C+<D+<E+<F = 360°

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