in the given figure find the value of secant a
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EXPLANATION.
In the given figure.
Value of secα.
As we know that,
⇒ In ΔABC.
⇒ AB = 4cm.
⇒ BC = 3cm.
By using Pythagoras theorem, we get.
⇒ H² = P² + B².
Hypotenuse > Perpendicular > Base.
⇒ (AC)² = (AB)² + (BC)².
⇒ (AC)² = (4)² + (3)².
⇒ (AC)² = 16 + 9.
⇒ (AC)² = 25.
⇒ AC = √25.
⇒ AC = 5 cm.
Now, again we can see that,
⇒ In ΔACD.
⇒ AC = 5cm.
⇒ CD = 12cm.
Again using Pythagoras theorem, we get.
⇒ H² = P² + B².
Hypotenuse > Perpendicular > Base.
⇒ (AD)² = (AC)² + (CD)².
⇒ (AD)² = (5)² + (12)².
⇒ (AD)² = 25 + 144.
⇒ (AD)² = 169.
⇒ AD = √169.
⇒ AD = 13 cm.
As we know that,
⇒ secθ = Hypotenuse/Base.
⇒ secα = 13/12.
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