Question

In the given figure find the value of x ​

Answer 1

Step-by-step explanation:

in ∆ABC and ∆ADC

angle BAC = angle ADC (90°)

angle BCA = angle ACD (common)

so ∆ABC similar to ∆ADC

Now

BC/AC = AC/DC

20*4 = x^2

x = sqrt80 = 4sqrt5