Question

In the given figure, find the value of x:​

Answer 1

As the angles on a straight line are known as straight line angles and have sum of 180 degree

So,

EBO+ BDC+ CBF = 180

(x+3)+(x+20)+ (x+7) =180

3x + 30 = 180

3x =180-30

3x= 150

x= 150/3

x = 50

PLZ MARK AS THE BRAINLEST

Answer 2

Answer:

($x+3$)° + ($x+20$)° + ($x+7$)° =$180$°

$3x+$($3+20+7$) = $180$°

$3x +$$30$ = $180$°

$3x$ = $180 - 30$

$3x$ = $150$

$x$ = $\frac{150}{3}$

$x$ = $50$

$So,$

• $x+3$ = $50+3$ = $53$

• $x+20$ = $50+20$ = $70$

• $x+7$ = $50+ 7$ = $57$