Question

In the given figure, find the value of x:​

Answer 1

Given :

• ∠EBD = x+3°
• ∠DBC = x+20°
• ∠CBF = x+7°

To Find :

• Value of x.

Solution :

As we know that the sum of angles made on one line is 180°.So,

$\longmapsto\tt{\angle{EBD}+\angle{DBC}+\angle{CBF}=180\degree}$

$\longmapsto\tt{x+3+x+20+x+7=180\degree}$

$\longmapsto\tt{3x+30=180\degree}$

$\longmapsto\tt{3x=180\degree-30\degree}$

$\longmapsto\tt{3x=150\degree}$

$\longmapsto\tt{x=\cancel\dfrac{150}{3}}$

$\longmapsto\tt\bold{x=50}$

So , The value of x is 50...

_______________________

VERIFICATION :

$\longmapsto\tt{x+3+x+20+x+7=180\degree}$

$\longmapsto\tt{50+3+50+20+50+7=180\degree}$

$\longmapsto\tt\bold{180\degree=180\degree}$

HENCE VERIFIED

Answer 2

Step-by-step explanation:

∠EBD+∠DBC+∠CBF=180°

\longmapsto\tt{x+3+x+20+x+7=180\degree}⟼x+3+x+20+x+7=180°

\longmapsto\tt{3x+30=180\degree}⟼3x+30=180°

\longmapsto\tt{3x=180\degree-30\degree}⟼3x=180°−30°

\longmapsto\tt{3x=150\degree}⟼3x=150°

\longmapsto\tt{x=\cancel\dfrac{150}{3}}⟼x=

3

150

\longmapsto\tt\bold{x=50}⟼x=50

So , The value of x is 50.....