Question

In the given figure, find the value of x:​

Answer 1

Answer:

angle ebd+dbc+cbf=180

=(x+3) +(x+20) +(x+7) =180

=x+3+x+20+x+7=180

3x+30=180

3x=180-30

3x=150

x=150/3

x=50

value of angle ebd= (x+3) =50+3=53

dbc=(x+20) =50+20=70

cbf= (x+7) =50+7=57

l hope this is helpful for u

Answer 2

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★ Sᴏʟᴜᴛɪᴏɴ :-

From the given figure ,

• There is a straight line EBF
• With angles ∠DBE = (x + 3)° , ∠DBC = (x + 20)° & ∠CBF = (x + 7)°

Using straight line property ,

Straight line property :- Sum of all angles on a straight line is always equal to 180°

Similarly ,

Sum of all angles on the given straight line EBF equal to 180°

∠DBE + ∠DBC + ∠CBF = 180°

Substituting the values of the given angles,

⇒ (x + 3)° + (x + 20)° + (x + 7)° = 180°

⇒ 3x° + 30° = 180°

Taking common

⇒ 3(x + 10)° = 180°

⇒ (x + 10)° = 180° ÷ 3

⇒ (x + 10)° = 60°

⇒ x° = 60° + 10°

⇒ x° = 70°

Hence , x° = 70°

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