Question

In the given figure, find the value of x:​

Answer 1

Answer:

solution ;

or,(x+3)°(x+20)°(x+7)°=180°[ sum of straight of angle is 180°]

or,3x+30°=180°

or,3x=180°-30°

or,3x=150°

or,x=150°÷3

or,x=50°

therefore the value of x is 50°.

Answer 2

Given:

∠ EBD = ($\:x+3$)°

∠ DBC = ($\:x+20$)°

∠ CBF = ($\:x+7$)°

To find:

The value of $x$.

Solution:

We know that,

Sum of angles on a straight line = $180°$

↬∠ EBD + ∠ DBC + ∠ CBF = $180°$

↬($x+3$)° + ($x+20$)° + ($x+7$)°= $180°$

Collect like terms.

↬$(x+x+x)$ + $(3+20+7)$° = $180°$

↬$3x$ + $30°$ = $180°$

↬$3x$ = $180°-30°$

↬$x$ = $\frac{150 }{3}$

↬$x$ = $50°$

$\sf\pink{Therefore,\:the\:value\:of}$ $x$ $\sf\pink{is}$ $\boxed{ 50° }$.

Also, the three angles are $\boxed{ 53° }$, $\boxed{ 70° }$ and $\boxed{ 57° }$ respectively.