Question

in the given figure , find the value of x


a) 40 degree
b) 50 "
c)60"
d)80"



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Answer 1

Answer:

x = 50°

Step-by-step explanation:

∠EBF = 180°      .........Straight angle

∠DBE + ∠DBC + ∠CBF = 180°

(x+3°) + (x+20°) + (x+7°) = 180°

3x + 3° + 20° + 7° = 180°

3x + 30° = 180°

3x = 180° - 30°

3x = 150°

x = 150°/3

x = 50°

Answer 2

Given:

A figure showing different angles on a straight line where angle DBE = (x + 3)°, angle DBC = (x + 20)°, angle CBF = (x + 7)°.

To find:

The value of x.

Solution:

As we know that the sum of all angles on one side of a straight line is equal to 180°.

Thus, from the figure we have,

angle DBE + angle DBC + angle CBF = 180°.

Also, according to the question, we have

angle DBE = (x + 3)°, angle DBC = (x + 20)°, angle CBF = (x + 7)°.

$(x + 3)° + (x + 20)° + (x + 7)° = 180°$

On solving the above equation, we get,

$3x + 30 = 180$

$3x = 150$

$x = 50$

Hence, the value of x is 50°.

So, the correct option is b) 50°.