Question

In the given figure find the value of x and y.

Answer 1

Step-by-step explanation:

√RPQ = √PQR..........1

√PQR = √RPQ..........2

√PRQ = 40°

√Y=40°

√RPQ + √PQR + √PRQ = 180°

√RPQ + √PQR + 40° = 180°

√RPQ + √PQR = 180° - 40° = 140°

1 and 2 find

2√RPQ = 140°

√RPQ = 140°/2

√RPQ = 70°

X = 70° AND Y = 40°

Answer 2

we know that

${\boxed{\sf{\red{sum\ of\ all\ angles\ is\ a\ triangle\ is\ 180°}}}}$

therefore,

x+x+y= 180° ........(i)

also

$\bold{x+x= 140°}$ ${\boxed{\sf{\red{exterior\ angle\ property}}}}$

$\bold{2x= 140°}$

$\bold{x= 70°}$

now in equation (i) we have,

$\bold{x+x+y=180°}$

$\bold{70°+70°+y=180°}$

$\bold{140°+y=180°}$

$\bold{y=180-140}$

$\bold{y=40°}$

Therefore all angle of a triangle are 70°,70° and 40°

hope it helps ☺️☺️