in the given figure find the value of x. help to solve
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see ,
angle CBA=180-120=60°(opposite angles of cyclic quad. are supplementary)
now,
in ∆ABC,
90+60+x=180(Angle ACB=90°since angles in the semicircle are 90°)
then....,
x=30°
answer:30°
angle CBA=180-120=60°(opposite angles of cyclic quad. are supplementary)
now,
in ∆ABC,
90+60+x=180(Angle ACB=90°since angles in the semicircle are 90°)
then....,
x=30°
answer:30°
nshree:
thanku
mine pleasure..did you get it
yeah
helped me v.much
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