Question

in the given figure, find the value of x....
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Answer 1

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Given :-

AB || CD || EF & /_FEC = 70° and /_ABC = 70°.

To Find :-

Value of x

Solution :-

As EF || CD

So, /_FEC + /_ECD = 180° (Sum of cointeriors)

=> 130° + /_ECD = 180°

=> /_ECD = 50°

Now, AB || CD

So, /_ABC = /_BCD ( Alternate interior angles)

So, 70° = /_BCE + /_ECD

=> 70° = x + 50°

=> x = 20°

Answer 2

Answer:

X = 20°

Step-by-step explanation:

Refer the attachment for the steps.....

is that ur test ??