Question

In the given figure Find the value of x where AB = 6cm, BC = 5cm ,AC = 5cm and angle B = 50°, angle A = 2x + 20° .

this is a question of class 9th
pls answer fast ......​

Answer 1

Answer:

15°

Step-by-step explanation:

angle A=angle B

(interior opposite Angle in isosceles triangle)

50°=2x+20°

50°-20°=2x

30°=2x

15°=x

Answer 2

Given,

$\[\begin{array}{l}AB = 6cm\\BC = 5cm\\AC = 5cm\\\angle B = 50^\circ \\\angle A = 2x + 20^\circ \end{array}\]$

Solution,

Calculate the value of x.

According to triangular property if two sides of the triangle are of equal length then their corresponding angles will also be same.

$\[\begin{array}{l}BC = AC\\ \Rightarrow \angle A = \angle B\\ \Rightarrow 2x + 20^\circ = 50^\circ \\ \Rightarrow 2x = 30^\circ \\ \Rightarrow x = 15^\circ \end{array}\]$

Hence the value of x is $\[15 \]$.