In the given figure find the value of x + y + z.
(A) 180°
(B) 225°
(C) 195°
(D) 210°
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the answer is d)210
y=90...........angles in linear pair
y+z+50=180........?.sim of all angles of triangle
z=40
x=80
x+y+z=80+90+40
=210
y=90...........angles in linear pair
y+z+50=180........?.sim of all angles of triangle
z=40
x=80
x+y+z=80+90+40
=210
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