Question

In the given figure, find value of angle theta,if ab=20cm,bc=20√3

Answer 1

Answer:

theta=30°

Step-by-step explanation:

tan(theta)= opposite/adjacent=AB/BC=20/20√3=1/√3

so, theta=30°

Answer 2

The value of angle is $30^{\circ}$.

Explanation:

According to the trignometry ABC,

$\tan\theta=\dfrac{\text{Perpendicular}}{\text{Base}}$

In the given right-triangle ABC, we have AB = 20 cm and BC = $20\sqrt{3}$.

$\tan \theta =\dfrac{AB}{BC}\\\\=\dfrac{20}{20\sqrt{3}}\\\\=\dfrac{1}{\sqrt{3}}$

Since ,

$\tan30^{\circ}=\dfrac{1}{\sqrt{3}}\\\\\Rightarrow\ \theta = 30^{\circ}$

Hence , the value of angle is $30^{\circ}$.

# Learn more :

In a right angled trianle ABC in which angle b=90°,angle a=30°and AC=20cm

Find BC and AB

https://brainly.in/question/7791561