in the given figure find x
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Answered by
2
Hi friend,
We know that,
x°+31+x°+20+x°=180°
3x°+51°=180°
3x°=180°-51°
3x°=129°
x°=129°/3
x=43°
x+31=43+31=74°
x+20=43+20=73°
x=43°
hope it helps
We know that,
x°+31+x°+20+x°=180°
3x°+51°=180°
3x°=180°-51°
3x°=129°
x°=129°/3
x=43°
x+31=43+31=74°
x+20=43+20=73°
x=43°
hope it helps
Answered by
2
Hey there !
∠1 = x° + 31
∠2 = x° + 20
∠3 = x°
∠1 + ∠2 + ∠3 = 180° [ Straight angle ]
x° + 31 + x° + 20 + x° = 180°
3x + 51 = 180 °
3x = 180 - 51
3x = 129
x = 129/3
x = 43°
∠1 = x° + 31
∠2 = x° + 20
∠3 = x°
∠1 + ∠2 + ∠3 = 180° [ Straight angle ]
x° + 31 + x° + 20 + x° = 180°
3x + 51 = 180 °
3x = 180 - 51
3x = 129
x = 129/3
x = 43°
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