In the given figure find x and y
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a.
y is an exterior angle which is the sum of x and 90(being opposite interior angles)
x=90÷2= 45(isosceles triangles so base angles are same)
thus y is 90+45=135
b. y=180-60=120
(opposite angles of a quadrilateral are supplementary)
x=360-y
=360-120= 240
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