Question

In the given figure find x,y values . pls pls ans this step by step ​

Answer 1

$\mathbb{SOLUTION}\rightarrow$

$\implies \angle$ BDE + $\angle$ DBE = $\angle$ AED

( exterior angle sum property )

$\implies$ 40⁰ + $\angle$ x = 130⁰

$\implies \angle$ x = 130⁰ - 40⁰

$\implies \angle$ x = 90⁰

again ,

$\implies \angle$ EBC + $\angle$ x = 180⁰ ( linear pair )

$\implies \angle$ EBC = 180⁰ - 90⁰

$\implies \angle$ EBC = 90⁰

let ,

$\implies$ $\angle$ ACB = y⁰

$\therefore$

$\implies$ $\angle$ ACB + y⁰ + $\angle$ ABC = 180⁰

( angle sum property of ∆ )

$\implies$ y⁰ + y⁰ + 90⁰ = 180⁰

$\implies$ 2y⁰ = 180⁰ - 90⁰

$\implies$ y⁰ = $\frac{90⁰}{2}$

$\implies$ y⁰ = 45⁰

$\boxed{showed}$