In the given figure, find x +y + z
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360°
x+y+z=360°
External angles of Triangle.
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In the Given Figure,
Consider the triangle MNO, We know that, sum of measures of interior angles of triangle is equal to 180°
∠M + ∠N + ∠O = 180°
∠M + 70° + 90° = 180°
160 ° + ∠M = 180°
∠M = 180 ° - 160
∠M = 20°
We know that, sum of angles linear pair is equal to 180 °
So , x + 90 = 180°
x = 180° - 90°
x = 90°
Then y + 70° = 180°
y = 180° - 70°
y = 110 °
Similarly
z + 20 = 180°
z = 180 ° - 20
z = 160°
Hence, x + y + z
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