In the given figure, find ×, y, z. (whichever is required)
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answer is in the attachment
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x=100
the sum of triangle∆=180
therefore some of all sides
100+40+x=180
140+x=180
x=180-140
x=40
similarly 100+40+40=180
y180 =180
y180-180
y=0
similarly 180+0z=180
z=180-180
z=0
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