Question

In the given figure find ZPQR (where O is centre of the circle)​

Answer 1

Step-by-step explanation:

in triangle POQ is an isosceles triangle (PO and OQ is the radius)

then,

angleOPQ= angle OQP

2angleOPQ+80°=180°

2angleOPQ=100°

angleOPQ=50°=angleOQP

in triangle QOR is an isosceles triangle (QO and OR is the radius)

then,

angleOQR=angleORQ

2angleOQR+120=180

2angleOQR=60

angle OQR=30

anglePQR=anglePQO+angle OQR

angle PQR=50°+30°

angle PQR=80

Hence we can say that option b is correct

(please mark me as brainlist because it takes a time to type that much on key pad❤)