Math, asked by radheyshyamm, 1 year ago

in the given figure.,from a cuboidal solid metalic block of dimensiins 15cm×10cm×5cm a cylindrical hole of diameter 7cm is drilled out . find the surface area of the remaining block.

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Answers

Answered by sadikalisait
8

Answer:


Step-by-step explanation:FIGURE IS IN THE ATTACHMENT

SOLUTION:


GIVEN:

Length of the cuboidal solid metallic block(l) = 15 cm.

Breadth of the cuboidal solid metallic block(b) = 10 cm.

Height of the cuboidal solid metallic block = height of the cylinder (h) =  5 cm.


Diameter of a cylindrical hole(d)= 7 cm

Radius of a cylindrical hole = d/2 = 7/2


Surface area of a cuboid = 2(lb + bh + hl)

Surface area of a cuboid = 2(15×10 + 10×5 + 5×15)

= 2 (150 + 50 + 75) = 2 × 375 = 550 cm²


Curved surface Area of a cylinder = 2πrh

= 2 × (22/7) × (7/2) × 5 = 22 × 5 = 110 cm²


Area of  2 cylindrical holes = 2(πr²)

= 2 × (22/7) × (7/2)²

= 2 × (22/7) × (7/2) × (7/2)

= 11 × 7

= 77 cm²


Surface area of the remaining block = surface area of the cuboidal block +CSA of cylinder - Area of  2 cylindrical holes


Surface area of the remaining block = 550 + 110 - 77

= 660 -77

= 583 cm².


Hence, the Surface area of the remaining block = 583 cm².


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radheyshyamm: thank u so much .....
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