in the given figure gh is parallel to no.nr bisects angle mno and or bisects angle mon.show that gh =ng+oh
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Given : GH || NO , NR bisects angle MNO and or bisects angle mon.
To Find : show that GH =NG+OH
Solution:
GH || NO
∠GRN = ∠ONR ( alternate angle)
∠GNO = ∠MNO as G is on line MN
∠GNR = ∠ONR as NR bisects ∠MNO
=> ∠GRN = ∠GNR
=> GN = GR
Similarly
∠NOR = ∠HRO
∠NOR = ∠HOR as OR bisects ∠MON
=> ∠HRO = ∠HOR
=> OH =HR
GN + OH = GR + HR
=> GN + OH = GH
QED
Hence Proved
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