In the given figure
given figure de l's parallel
to Bc AD=6cm DB=8 on Ae =90m
them ec is
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Answer:
In ∆ ADE and ∆ ABC
< A = < A ( Common Angle)
< ADE = < ABC
< AEC = < ACB
Therefore,
∆ ADE =∆ ABC. (AAA Test)
AE/EC = AD/DB
90cm/ EC = 6cm/8cm
EC = 90x8/6 cm
EC = 120 cm
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