Question

In the given figure
given figure de l's parallel
to Bc AD=6cm DB=8 on Ae =90m
them ec is​

Answer 1

Answer:

In ∆ ADE and ∆ ABC

< A = < A ( Common Angle)

< ADE = < ABC

< AEC = < ACB

Therefore,

∆ ADE =∆ ABC. (AAA Test)

AE/EC = AD/DB

90cm/ EC = 6cm/8cm

EC = 90x8/6 cm

EC = 120 cm