Question

In the given figure how much angle a is greater than angle b:
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Answer 1

In ∆ ABD ,

• ∠ A = 48°
• ∠ D = 90°
• ∠ B = ??

Sum of 3 angles in a triangle 180° .

then ,

∠A + ∠B + ∠D = 180°

$\sf ∠B = 180 - 48 - 90 = 52 \degree$

$\huge \sf \angle B = 52 \degree$

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Answer 2

Answer:

By 26°

Step-by-step explanation:

360°-338=22°

in triangle ADB

48°+90°+b=180°

138°+b=180°

b =180°-138°

b=42°

In triangle ADC

22°+90°+a=180°

112°+a=180°

a=180°-112°

a=68°

difference=68°-42°=26°