in the given figure,I l l m and n Is transversal. if angle 1 is twice of angle two then find all the angles
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let the angle 2 be x
then, angle 1 =2x
angle 1+ angle 2= 180 (by sum of all angle of
triangle)
2x + x = 180
3x = 180
x = 180/3
x = 60
then, angle 1 = 2x =2×60 = 120
angle 2= x = 60
angle 2=angle 3 (by v.o.a)
angle 3 = 60
angle 1 = angle 4 (by v.o.a)
angle 4= 120
angle 4=angle 5 (by a.i.a)
angle 5 = 120
angle 3=angle 6 (by a.i.a)
angle 6= 60
angle 5= angle 8 (by v.o.a)
angle 8= 120
angle 6= angle 7 (by v.o.a)
angle 7= 60
Hence,
angle 1=120
angle 2=60
angle 3=60
angle 4=120
angle 5=120
angle 6=60
angle 7=60
angle 8=120
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