In the given figure, (i) name the median and the altitude. Here E is the midpoint of BC. *
1 point
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a ) BD-Altitude, AE-median
b) AE-Altitude, AD-median
c) AD-Altitude, AE-median
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Answered by
27
Answer:
AD-Altitude, AE-median
Answered by
16
Solution :-
We know that,
- The perpendicular segment from a vertex of a triangle to the opposite side is altitude .
as we can see that, In ∆ABC , The segment from vertex A is perpendicular at point D on the opposite side BC .
Therefore,
→ AD = Altitude .
Now, we know that,
- A line segment drawn from a vertex to the midpoint of the opposite side of the triangle is median .
given that, E is mid point of BC .
As we can see that, the line segment from vertex A cuts opposite sides BC at mid point E .
Therefore,
→ AE = Median .
Hence, Option (C) AD - Altitude, AE - Median is correct answer .
Learn more :-
In the figure ∠ MNP = 90°, ∠ MQN = 90°, , MQ = 12 , QP = 3 then find NQ .
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