Math, asked by abhicr08, 8 months ago

In the given figure, (i) name the median and the altitude. Here E is the midpoint of BC. *
1 point
Captionless Image
a ) BD-Altitude, AE-median
b) AE-Altitude, AD-median
c) AD-Altitude, AE-median

Answers

Answered by love9899
27

Answer:

AD-Altitude, AE-median

Answered by RvChaudharY50
16

Solution :-

We know that,

  • The perpendicular segment from a vertex of a triangle to the opposite side is altitude .

as we can see that, In ∆ABC , The segment from vertex A is perpendicular at point D on the opposite side BC .

Therefore,

→ AD = Altitude .

Now, we know that,

  • A line segment drawn from a vertex to the midpoint of the opposite side of the triangle is median .

given that, E is mid point of BC .

As we can see that, the line segment from vertex A cuts opposite sides BC at mid point E .

Therefore,

→ AE = Median .

Hence, Option (C) AD - Altitude, AE - Median is correct answer .

Learn more :-

In the figure ∠ MNP = 90°, ∠ MQN = 90°, , MQ = 12 , QP = 3 then find NQ .

https://brainly.in/question/47411321

show that AB2 = AD.AC

https://brainly.in/question/47273910

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