In the given figure, if /_2=120*and/_5=60*, then show that a ll b.
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In a triangle `A B C` , if `B=30^0a n d c= play. 1:26 · In Figure, if `E C A B ,\ /_E C D=70^0A N D. play. 1:58 · In Figure, given ...
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Given: Angle 2 = 120, Angle 5 = 60, P is the transversal.
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Solution:
Here, Angle 2 is given to be 120.
As Angle 2 and Angle 1 form a linear pair, the sum of the angles must be 180.
Angle 2 + Angle 1 = 180
120 + Angle 1 = 180
Angle 1 = 180 - 120
= 60
But, Angle 5 is given to be 60.
Thus, Angle 1 = Angle 5 = 60As the corresponding angles are equal, m is parallel to n.
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