In the given figure, if ∠A= 75° and CE ∥ AB. If ∠ECD= 40°, find the other two angles of the △
ABC.
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Answer:
40,75,65
Step-by-step explanation:
given CE is parallel to AB.
so since angle, ABC ,and angle ECD are corresponding angles...
they are equal.
So angle ABC is 40 i.e <B = 40 °
in a triangle sum of angles is 180°.
so <A + <B + <ACB = 180
i.e 75 + 40 + <ACB =180.
<ACB = 65°.
hence 40° ,75°,65° are all angles in triangle
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