in the given figure if a b parallel CD and angle bdc is equal to 30 degree and Angle B a d is equal to 80 degree find angle X angle Y and angle Z
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angle cdb will be equal to abd (alternate interior angles)
=30
in triangle abd
by angle sum prop
30+80+y=180
y=180-30-80
y=70
in triangle dcb
y-30=70-30=40
now by angle sum property,
40+30+z=180
z=180-40-30
z=110
x=30, y=70, z=110
Hope this helps :)
=30
in triangle abd
by angle sum prop
30+80+y=180
y=180-30-80
y=70
in triangle dcb
y-30=70-30=40
now by angle sum property,
40+30+z=180
z=180-40-30
z=110
x=30, y=70, z=110
Hope this helps :)
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