In the given figure, if ∠A = ∠C and AB = BC, then show that ∆ CBE≅∆ ABD
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In ∆ CBE and ∆ ABD
∠A = ∠C (given)
AB = BC (given)
∠B = ∠B (common)
∆ CBE≅∆ ABD (ASA congruence)
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