in the given figure. if AB=CD, AD = BC then prove.angle A= angle C
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ABCD is a quadrilateral
In which
AB=CD
AD=BC
So it is also a parallelogram
Now
Since AB is parallel to CD therefore let AD be the transversal
Angle A + Angle D =180° (co-interior angle).............(I)
Let angle A be x and angle D=180-x
Now again AD is parallel to BC let CD be the transversal
Angle D+ Angle C = 180° (co-interior angles)
180-x+ angle C =180° (from I)
Angle C=x ....(ii)
Now from I and ii
Angle A = Angle C
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