Question

In the given figure, if AB ∥ CD and BC ∥ DE then prove that ∠B =∠D.

Answer 1

Step-by-step explanation:

∠CDE = ∠BCD [Alternate Interior angles, since BC ∥ DE]......(1)

∠ABC = ∠BCD [Alternate Interior angles, since AB ∥ CD ].......(2)

By Comparing both the $equations$, we get,

∠ABC = ∠CDE

=> ∠B = ∠D

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Answer 2

Step-by-step explanation:

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