Question

In the given figure - if AB//CD, angle BPQ = (5x+20)and angle PQD = (2x-10) , find the value of 'y' and 'Z '

Answer 1

Answer:

y = z = 38.58°

Step-by-step explanation:

Answer 2

The correct answer is y = 38.6° and z = 38.56°.

Given: ∡BPQ = 5x+20 and ∡PQD = 2x-10.

To Find: The value of y and z.

Solution:

As ∡BPO and ∡PQD are co interior angle.

5x + 20 + 2x - 10 = 180°

7x + 10 = 180°

7x = 170°

x = 24.28°.

∡BPQ = 5x+20 = 5(24.28) + 20

∡BPQ = 141.4°

∡PQD = 2x-10  = 2(24.28) - 10

∡PQD = 38.56°

According to the figure, ∡BPQ and y are linear pair.

∡BPQ + y = 180

y = 180° - ∡BPQ

y = 180° - 141.4°

y = 38.6°

According to the figure, z and ∡PQD are vertically opposite angles.

z =  ∡PQD

z = 38.56°

Hence, y = 38.6° and z = 38.56°.

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