In the given figure, if AB||CD, ∠APQ=50° and ∠PRD=127°, find x and y.
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Answered by
540
Hi , there !!
AB || CD
< APQ = < PQR { alternate interior Angle }
< APQ = 50 ° = < x
< X = 50 °
< x + < y = 127 ° { sum of two interior angle equal to exterior angle }
50 ° + <y = 127°
<Y = 127- 50
< Y = 77
thanks !!
Ranjan
AB || CD
< APQ = < PQR { alternate interior Angle }
< APQ = 50 ° = < x
< X = 50 °
< x + < y = 127 ° { sum of two interior angle equal to exterior angle }
50 ° + <y = 127°
<Y = 127- 50
< Y = 77
thanks !!
Ranjan
Answered by
276
Hola Sir!!
Your answer :-
a) To find x°
=> Angle APQ = 50°
=> Angle APQ = x° = 50° ( alternate interior angles )
b) To find y°
=> Angle PRD = 127°
=> 127° = x° + y°
=> 127° = 50° + y°
=> 127° - 50° = y°
=> 77° = y°
Hence, x° = 50°, y° = 77°
☆ Hope it helps ☆
Your answer :-
a) To find x°
=> Angle APQ = 50°
=> Angle APQ = x° = 50° ( alternate interior angles )
b) To find y°
=> Angle PRD = 127°
=> 127° = x° + y°
=> 127° = 50° + y°
=> 127° - 50° = y°
=> 77° = y°
Hence, x° = 50°, y° = 77°
☆ Hope it helps ☆
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