Question

In the given figure, if AB ∥ CD, ∠BPQ = (5 − 20)° and ∠ PQD = (2 − 10)°, then find the value of and .
pls its urgent

Answer 1

Since,
Angle BPQ and DQP sum up to form 180 degree
Adding them and equalising it to 180
We get x as 30 degree

Now,
Y + 5x-20= 180 degree. (Linear pair)
We know x=30.. putting in equation
We get y=50degree

For z,
Z=2x-10. (Vertically opp. Angles)
Z=50 degree