In the given figure, if AB || CD, CD || EF and y : z = 3: 7, find x.
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We are given that AB || CD ,and.∠PRD = 127°
We need to find the value of x and y in the figure.
∠APQ = x = 50°(Alternate interior angles)
∠PRD = ∠APR = 127°(Alternate interior angles)
∠APR = ∠QPR + ∠APQ
127° = y + 50°
y = 77°
Therefore, we can conclude that .
x = 50° and y = 77°
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