Question

In the given figure ,if AB||DC.If X=3/4
y=3/8z,
find the value of x,y,z​

Answer 1

Answer:

Given: AB|| DC; x= 4/3 y and y= 3/8z

AB|| DC

= < ABC = < BDC (Alternate Angles)

In ∆BDC

x+y+z = 180°

= 4/3y + 3/8z + z=180°

First we will solve the 4/3y

4/3y (since he value of y= 3/8z)

4/3x 3/8z

12/24z

1/2z

Now, 1/2z+3/8+z+z = 180°

After taking L.C.M. we get,

=(4z+3z+8z)/8= 180°

= 15z = 180×8

= z= 1440/15

= z = 96°

y = 3/8z

y= (3×96)/8

= y = 288/8

y= 36°

x= 4/3y

x= (4x36)×3

x= 144/3

x= 48°