in the given figure,if AB||DE,angleBAC=35 and angleCDE=53 find angleDCE
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Ganeshrock00:
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Since AB||DE,
angle BAC = angle CED = 35°
In triangle DCE,
By Angle Sum Property, we have,
angle DCE + angle CDE + angle CED = 180°
=> 53° + 35° + angle DCE = 180°
=> 88° + angle DCE = 180°
=> angle DCE = 180° - 88°
=> angle DCE = 92°
angle BAC = angle CED = 35°
In triangle DCE,
By Angle Sum Property, we have,
angle DCE + angle CDE + angle CED = 180°
=> 53° + 35° + angle DCE = 180°
=> 88° + angle DCE = 180°
=> angle DCE = 180° - 88°
=> angle DCE = 92°
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