Question

in the given figure if AB//de then X=?​

Answer 1

$here \: is \: your \: answer: \: \\ < abc \: + < bac + < acb = 180° \\ 50° + 75° + < acb = 180° \\ 125° + < acb = 180° \\ < acb = 180° - 125° \\ < acb = 55° \\ now < acb = < dce = 55° \\ < dce + < cde + < ced = 180°(angle \: sum \: property) \\ 45° + 55° + x = 180° \\ 100° + x = 180° \\ x = 180° - 100° \\ x = 80° \\ \\ hope \: it \: helps \: you.$