Question

In the given figure if AB||DE, ZBAC = 35º and
Z CDE = 53°, find ZDCE.
​

Answer 1

Given, AB║DE;

So, ∠BAC = ∠DEC  {Alternate Angles}

∠DEC = 35°

In ΔCED;

∠DEC + ∠CDE + ∠DCE = 180°  {Angle Sum Property of a Triangle}

35 + 53 + ∠DCE = 180

∠DCE = 180 - 88

∠DCE = 92°

Answer 2

Answer:

AB llDE

Step-by-step explanation:

CED=BAC=35°{alternative interior angles}

CED=BAC=35°{alternative interior angles} In ∆DEC,

CED=BAC=35°{alternative interior angles} In ∆DEC, CDE+CED+DCE=180°

CED=BAC=35°{alternative interior angles} In ∆DEC, CDE+CED+DCE=180° 53°+35°+DCE=180°

CED=BAC=35°{alternative interior angles} In ∆DEC, CDE+CED+DCE=180° 53°+35°+DCE=180° 88°+DCE=180°

CED=BAC=35°{alternative interior angles} In ∆DEC, CDE+CED+DCE=180° 53°+35°+DCE=180° 88°+DCE=180°DCE=180°-88°

CED=BAC=35°{alternative interior angles} In ∆DEC, CDE+CED+DCE=180° 53°+35°+DCE=180° 88°+DCE=180°DCE=180°-88°DCE=92°