In the given figure if AB intersects CD at P find <BDP
Answers
Answered by
0
Answer:
....................................................where is the image?
Answered by
2
Answer:
45°
Step-by-step explanation:
In ∆ACP
L P= 180°-(L A+ L C)
= 180°-(50°+55°)
=75°
In ∆ADP
L D=180° -(L B + L P)
180°-(60°+75°)
=45°
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