Question

In the given figure if AB intersects CD at P find <BDP​

Answer 1

Answer:

in triangle acp

55+50+x =180⁰ (angle sum property)

x=180-105

x=75⁰

now angle apc=bpd (vertically opp. angles)

bpd=75⁰

in triangle bpd

60+55+y=180⁰

y= 180-115

y =<bdp=65⁰

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