Question

in the given figure , if AB ll ED , then find the value of x

Answer 1

∠ECF = 180° - ∠DCF
           = 180° - 62
           = 118°
In ΔCEF,
∠ECF + ∠CEF + ∠EFC = 180°
  
118° + 36° + x = 180°
x = (180° - 36°- 118°)
   =  26°
∴ The value of x is 26°

Answer 2

Answer:

✮requried answer:

$let \: angle \: FCE = a \\ \\ 62 °+ a = 180° \\ \\ a = 180° - 62° \\ \\ °a = 180° \\ \\ \\ 36 °+ a + x = 180° \\ \\ 36° + 118° + x = 180 °\\ \\ 154 °+ x = 180 °\\ \\ x = 180° - 154° \\ \\ x = 26°$