In the given figure, if AB parallel CD, Angle YXB = 140 degree and Angle YZC = 35 degree then Angle XYZ =?
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In the given figure, AB || CD. Find the value of x, y and z.
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It is given that AB || CD and BC is a transversal
From the figure we know that ∠ABC = ∠BCD
So we get
x = 35
It is also given that AB || CD and AD is a transversal
From the figure we know that ∠BAD = ∠ADC
So we get
z = 75
According to the △ ABO
We can write
∠ABO + ∠BAO + ∠BOA = 180o
By substituting the values
xo + 75o + yo = 180o
35o + 75o + yo = 180o
On further calculation
yo = 180o - 35o - 75o
By subtraction
yo = 180o – 110o
yo = 70o
Therefore, the value of x, y and z is 35, 70 and 75.
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