Question

In the given figure if AB parallel to CD, angle APQ=50 degree and angle PRD=127 degree, find x and y

Answer 1

127 = 50
so , y = 50
127-50 = 77
value of x = 50
y = 77

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Answer 2

Given AB || CD
∆ APQ = 50° , ∆ PRD = 127°
So x= 50°
Now ,y + 50° = 127°
y =127°- 50°
y = 77°
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