Question

in the given figure if ABCD is a rectangle in which angle APB equal hundred degree then find the value of x ​

Answer 1

Given : A figure of rectangles in which angle APB equal 100 degree

To find : Value of x

Solution:

APC is a straight line

=> ∠APB + ∠CPB = 180°

=> 100° + ∠CPB = 180°

=> ∠CPB = 80°

Now AC & BD are Diagonal of Rectangles

Diagonal of rectangles are Equal in length & Bisect Each other

=> AP = BP = CP = DP = AC/2 = BD/2

Hence in Δ BPC

BP = BC

=> ∠PCB = ∠PBC = x

∠PCB +  ∠PBC + ∠CPB = 180°

=> x + x + 80° = 180°

=> 2x =  100°

=> x = 50°

Value of x = 50

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Answer 2

ANSWER

50

Is right answer