Question

in the given figure ,if ABCD is a rhombus ,diagonals ac and bd intersects at o and e is a point lying on the circle with centre o ,then some of the measures of bae and edc angles

Answer 1

AC is diameter of circle.
So , a(ABC) = 90°(a stands for angle)
But ∆ABC is an isosceles ∆ with AB = BC So, a(BAC) = a(BCA) = 90/2 = 45°
a(BAC) = a(BDC) = 45°
Also , a(BAE) = a(BDE)
a(BAE) + a(EDC) = a(BDE) + a(EDC) =a(BDC)=45