in the given figure if ac=ae AB=AD ANGLE BAD = ANGLE EAC THEN prove that angle ADE = ANGLE ABD
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Given: In figure, AC = AE, AB = AD and ∠BAD = ∠EAC.
To Prove: BC = DE.
Proof: In ∆ABC and ∆ADE,
AB = AD | Given
AC = AE | Given
∠BAD = ∠EAC | Given
⇒ ∠BAD + ∠DAC = ∠DAC + ∠EAC
| Adding ∠DAC to both sides
⇒ ∠BAC = ∠DAE
∴ ∆ABC ≅ ∆ADE | SAS Rule
∴ BC = DE. | C.P.C.T.
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